document.write( "Question 128590: The given function is \"f%28x%29=20000-15x\"\r
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\n" ); document.write( "\n" ); document.write( "Find \"f%5E%28-1%29%2850%29\"
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Algebra.Com's Answer #94079 by jim_thompson5910(35256)\"\" \"About 
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\"f%28x%29=20000-15x\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "To find \"f%5E%28-1%29%28x%29\", simply swap x and f(x) to get \r
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\n" ); document.write( "\n" ); document.write( "\"x=20000-15f%28x%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"15f%28x%29%2Bx=20000\" Add 15f(x) to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"15f%28x%29=20000-x\" Subtract x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%2820000-x%29%2F15\" Divide both sides by 15 to isolate f(x)\r
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\n" ); document.write( "\n" ); document.write( "So the inverse function is \"f%5E%28-1%29%28x%29=%2820000-x%29%2F15\" \r
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\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29%2850%29=%2820000-50%29%2F15\" Now plug in \"x=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29%2850%29=%2819950%29%2F15\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29%2850%29=1330\" Divide\r
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