document.write( "Question 128459:  
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document.write( "Find three consecutive even integers such that the sum of the first and third exceeds one half the second by 15 \n" );
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| Algebra.Com's Answer #94037 by checkley71(8403)      You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE THREE CONSECUTIVE EVEN INTEGERS. \n" ); document.write( "X+(X+4)=(X+2)/2+15 \n" ); document.write( "2X+4=(X+2+30)/2 \n" ); document.write( "2X+4=(X+32)/2 NOW CROSS MULTIPLY \n" ); document.write( "2(2X+4)=X+32 \n" ); document.write( "4X+8=X+32 \n" ); document.write( "4X-X=32-8 \n" ); document.write( "3X=24 \n" ); document.write( "X=24/3 \n" ); document.write( "X=8 ANSWER FOR THE FIRST INTEGER. \n" ); document.write( "8=2=10 THE SECOND INTEGER. \n" ); document.write( "8=4=12 THE THIRD INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "8+12=10/2+15 \n" ); document.write( "20=5+15 \n" ); document.write( "20=20 \n" ); document.write( " \n" ); document.write( " |