document.write( "Question 128437: A motorboat travels 120km upstream and then 120km downstream in a total of seven hours. If the speed of the river's current is 5km/h then what is the speed of the motorboat in still water????? \n" ); document.write( "
Algebra.Com's Answer #94027 by ankor@dixie-net.com(22740)\"\" \"About 
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A motorboat travels 120km upstream and then 120km downstream in a total of seven hours. If the speed of the river's current is 5km/h then what is the speed of the motorboat in still water.
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\n" ); document.write( "Let s = boat speed in still water
\n" ); document.write( "then
\n" ); document.write( "(s+5) = boat speed downstream
\n" ); document.write( "and
\n" ); document.write( "(s-5) = boat speed up-stream
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\n" ); document.write( "Write a time equation: Time = \"distance%2Fspeed\"
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\n" ); document.write( "Time up + time down = 7 hrs
\n" ); document.write( "\"120%2F%28%28s-5%29%29\" + \"120%2F%28%28s%2B5%29%29\" = 7
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\n" ); document.write( "Multiply equation by the common denominator: (s+5)(s-5), resulting in:
\n" ); document.write( "120(s+5) + 120(s-5) = 7(s-5)(s+5)
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\n" ); document.write( "multiply what's inside the brackets
\n" ); document.write( "120s + 600 + 120s - 600 = 7(s^2 - 25)
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\n" ); document.write( "240s = 7s^2 - 175
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\n" ); document.write( "0 = 7s^2 - 240s - 175; a quadratic equation
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\n" ); document.write( "This will factor to:
\n" ); document.write( "(7s + 5 )(s - 35) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "s = +35 km/hr is boat speed in still water
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\n" ); document.write( "Check solution using the time equation:
\n" ); document.write( "\"120%2F40\" + \"120%2F30\" =
\n" ); document.write( " 3 + 4 = 7 hrs\r
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