document.write( "Question 128437: A motorboat travels 120km upstream and then 120km downstream in a total of seven hours. If the speed of the river's current is 5km/h then what is the speed of the motorboat in still water????? \n" ); document.write( "
Algebra.Com's Answer #94027 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A motorboat travels 120km upstream and then 120km downstream in a total of seven hours. If the speed of the river's current is 5km/h then what is the speed of the motorboat in still water. \n" ); document.write( ": \n" ); document.write( "Let s = boat speed in still water \n" ); document.write( "then \n" ); document.write( "(s+5) = boat speed downstream \n" ); document.write( "and \n" ); document.write( "(s-5) = boat speed up-stream \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Time up + time down = 7 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by the common denominator: (s+5)(s-5), resulting in: \n" ); document.write( "120(s+5) + 120(s-5) = 7(s-5)(s+5) \n" ); document.write( ": \n" ); document.write( "multiply what's inside the brackets \n" ); document.write( "120s + 600 + 120s - 600 = 7(s^2 - 25) \n" ); document.write( ": \n" ); document.write( "240s = 7s^2 - 175 \n" ); document.write( ": \n" ); document.write( "0 = 7s^2 - 240s - 175; a quadratic equation \n" ); document.write( ": \n" ); document.write( "This will factor to: \n" ); document.write( "(7s + 5 )(s - 35) = 0 \n" ); document.write( ": \n" ); document.write( "Positive solution: \n" ); document.write( "s = +35 km/hr is boat speed in still water \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using the time equation: \n" ); document.write( " \n" ); document.write( " 3 + 4 = 7 hrs\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |