document.write( "Question 128289: hi!
\n" ); document.write( "if S= a over 1-r find s when a=10 and r=1/2
\n" ); document.write( " find s when a=4 and r=1/5
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #93968 by JessicaGill(40)\"\" \"About 
You can put this solution on YOUR website!
if \"S=a%2F%281-r%29\" find s when a=10 and r=1/2and find s when a=4 and r=1/5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Set up first problem and substitute values\r
\n" ); document.write( "\n" ); document.write( "\"s=10%2F%281-%281%2F2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Simplify \"1-%281%2F2%29=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Now we are at \"s=10%2F%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "There are two ways to do this and you will get the same answer.\r
\n" ); document.write( "\n" ); document.write( "1. Convert \"1%2F2\" to a decimal \".50\" and divide to get \"20=s\"
\n" ); document.write( "2. Multiply 10 by the reciprical of \"1%2F2\" which is \"2%2F1\" and you will still end up with \"s=20\"\r
\n" ); document.write( "\n" ); document.write( "\"%2810%2F1%29%2A%282%2F1%29=20%2F1\" or \"20\"\r
\n" ); document.write( "\n" ); document.write( "2nd problem
\n" ); document.write( "\"s=4%2F%281-%281%2F5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "First simplify \"1-%281%2F5%29=4%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Now there are two ways to cotinue as above
\n" ); document.write( "1. Convert \"4%2F5\" to a decimal \".80\" and divide \"4%2F.80=5\"
\n" ); document.write( "OR
\n" ); document.write( "2. Multiply 4 by the reciprical of \"4%2F5\" which is \"5%2F4\"
\n" ); document.write( " \"%284%2F1%29%2A%285%2F4%29=5\"
\n" ); document.write( "so \"s=5\" for the second problem\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!\r
\n" ); document.write( "\n" ); document.write( "Ms. G
\n" ); document.write( "
\n" );