document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128275>Question 128275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 1:30pm an airplane leaves Tucson for Miami a distance of 2240 miles. The plane flies at 280 mph. A second airplane leaves Tucson at 2:15pm and is scheduled to land in Miami 15 minutes before the first airplane. At what rate must the second airplane travel to arrive on schedule? PLEASE HELP!!!! THANK-YOU </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93964 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "amount of time it takes first plane to arrive in Miami=(d/r)=2240/280=8 hr.<BR>\n" );
document.write( "This means that first plane gets into Miami at 9:30pm and we are told that the second plane is scheduled to land at 9:15pm.  So, the second plane has to make the trip in (9:15-2:15)or 7 hrs.  Now we can easily calculate the rate of the second plane:\r<BR>\n" );
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document.write( "Rate of second plane=(d/t)=2240/7=320 mph\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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