document.write( "Question 128350: The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising , find its length and its width. \n" ); document.write( "
Algebra.Com's Answer #93962 by chitra(359)\"\" \"About 
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Let \"x\" ft be the width of the rectangle\r
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\n" ); document.write( "\n" ); document.write( "So lenght will be \"3 + x\" ft \r
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\n" ); document.write( "\n" ); document.write( "Given area = 40 ft^2\r
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\n" ); document.write( "\n" ); document.write( "We know that the area of the rectangle is given by lenght times breadth \r
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\n" ); document.write( "\n" ); document.write( "40 = x * (x + 3)\r
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\n" ); document.write( "\n" ); document.write( "40 = x^2 + 3x \r
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\n" ); document.write( "\n" ); document.write( "==> x^2 + 3x - 40 = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> by the method of factoring we find\r
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\n" ); document.write( "\n" ); document.write( "==> x^2 + 8x - 5x - 40 = 0\r
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\n" ); document.write( "\n" ); document.write( "==> x(x + 8) - 5(x + 8) = 0\r
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\n" ); document.write( "\n" ); document.write( "==> x = 5 Or x = -8 \r
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\n" ); document.write( "\n" ); document.write( "We dont consider the negative values of x.\r
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\n" ); document.write( "\n" ); document.write( "Therfore x = 5 ft will be the width\r
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\n" ); document.write( "\n" ); document.write( "and x + 3 = 5 + 3 = 8ft will be the lenght of the rectangle\r
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\n" ); document.write( "\n" ); document.write( "thus the solution
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