document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128347>Question 128347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sq root(x^2+5)=x+3\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93953 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sq root(x^2+5)=x+3 <BR>\n" );
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document.write( "Square both sides to get:<BR>\n" );
document.write( "x^2+5 = x^2+6x+9<BR>\n" );
document.write( "6x = -4<BR>\n" );
document.write( "x = -2/3<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Can x = -2/3 ?<BR>\n" );
document.write( "sqrt((4/9)+5) = -2/3 + 3<BR>\n" );
document.write( "sqrt(49/9) = 7/3<BR>\n" );
document.write( "7/3 = 7/3<BR>\n" );
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document.write( "Final Ans: x = -2/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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