document.write( "Question 128260: Jose left the airport and traveled toward the
\n" ); document.write( "mountains. Kayla left 2.1 hours later
\n" ); document.write( "traveling 35 mph faster in an effort to catch
\n" ); document.write( "up to him. After 1.2 hours Kayla finally
\n" ); document.write( "caught up. Find Jose's average speed. \n" ); document.write( "
Algebra.Com's Answer #93933 by ankor@dixie-net.com(22740)\"\" \"About 
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Jose left the airport and traveled toward the
\n" ); document.write( "mountains. Kayla left 2.1 hours later
\n" ); document.write( "traveling 35 mph faster in an effort to catch
\n" ); document.write( "up to him. After 1.2 hours Kayla finally
\n" ); document.write( "caught up. Find Jose's average speed.
\n" ); document.write( ":
\n" ); document.write( "Let s = J's speed
\n" ); document.write( "Then
\n" ); document.write( "(s+35) = K's speed
\n" ); document.write( ":
\n" ); document.write( "When K catches up with J they will have traveled the same distance
\n" ); document.write( ":
\n" ); document.write( "When K catches J their travel times will be:
\n" ); document.write( "K's time = 1.2 hrs
\n" ); document.write( "J's time = 1.2 + 2.1 = 3.3 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: Distance = time * speed
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\n" ); document.write( "J's dist = K's dist
\n" ); document.write( "3.3s = 1.2(s+35)
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\n" ); document.write( "3.3s = 1.2s + 42
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\n" ); document.write( "3.3s - 1.2x = 42
\n" ); document.write( ":
\n" ); document.write( "2.1s = 42
\n" ); document.write( "s = \"42%2F2.1\"
\n" ); document.write( "s = 20 mph is J's speed
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\n" ); document.write( "We can check our solution by finding the distance of each:
\n" ); document.write( "K: 1.2(20+35) = 66 mi
\n" ); document.write( "J: 3.3(20) = 66 mi, confirms our solution \n" ); document.write( "
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