document.write( "Question 19402: I do not understand how to solve these. Any help would be appreciated.
\n" ); document.write( " $\"+x%5E2-3x-18=0+\"$ \n" ); document.write( "

Algebra.Com's Answer #9388 by Earlsdon(6294) $\"\"$ $\"About$

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You could try factoring the polynomial.\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2+-+3x+-+18+=+0\"$ You need to find two integers whose product is -18 and whose sum is -3. (x + ? )(x + ?)\r
\n" ); document.write( "\n" ); document.write( "Try 3 X -6 = -18
\n" ); document.write( "3 + (-6) = -3
\n" ); document.write( " $\"%28x+%2B+3%29%28x+-+6%29+=+0\"$ = $\"x%5E2+-+3x+-+18+=+0\"$ So these are the correct factors.\r
\n" ); document.write( "\n" ); document.write( " $\"%28x+%2B+3%29%28x+-+6%29+=+0\"$ Apply the zero products principle.
\n" ); document.write( "(x + 3) = 0 and/or (x - 6) = 0
\n" ); document.write( "If x + 3 = 0 then, x = -3
\n" ); document.write( "If x - 6 = 0 then, x = 6\r
\n" ); document.write( "\n" ); document.write( "The roots are:
\n" ); document.write( "x = -3
\n" ); document.write( "x = 6\r
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