document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=128215>Question 128215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation of each line in standard form.  Passes through (-6,2) and (-2, 0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93879 by </B><A HREF=/tutors/aboutme.mpl?userid=ozymandias><B>ozymandias(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ozymandias><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider the equation is of the form y = mx + c<BR>\n" );
document.write( "(the question does not say, so I am going to assume it is a straight line)\r<BR>\n" );
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document.write( "Plug in the variables\r<BR>\n" );
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document.write( "2 = -6m + c\r<BR>\n" );
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document.write( "0 = -2m + c\r<BR>\n" );
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document.write( "Subtract the second from the first\r<BR>\n" );
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document.write( "2 = -4m\r<BR>\n" );
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document.write( "m = -0.5\r<BR>\n" );
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document.write( "Therefore c = - 1\r<BR>\n" );
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document.write( "The whole equation is y = -0.5x - 1 </SPAN>\n" );
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