document.write( "Question 128175: matthew is 3 times as old as jenny. In 7 years he will be twice as old as she will be then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #93866 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! m is Matthew's age now. j is Jenny's age now.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 7 years, Matthew will be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But we know that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Jenny is 7 now, and Matthew is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "In seven years Jenny will be 14 and Matthew will be 28. 28 = 2 * 14. Answer checks. \n" ); document.write( " \n" ); document.write( " |