document.write( "Question 128149: 20 men finished 1/4 of the house in 7 days.but they have to finish it in 5 more days. how many men shall be added to the crew so that they can finish the house? \n" ); document.write( "
Algebra.Com's Answer #93824 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 20 men finished 1/4 of the house in 7 days.but they have to finish it in 5 more days. how many men shall be added to the crew so that they can finish the house? \n" ); document.write( "---------------------------- \n" ); document.write( "# of men and # of houses completed are directly related \n" ); document.write( "# of men and # of days required are inversely related \n" ); document.write( "-------------- \n" ); document.write( "General Equation: \n" ); document.write( " men = k[h/d] \n" ); document.write( "Need to find \"k\" \n" ); document.write( "--------------- \n" ); document.write( "Your problem: \n" ); document.write( "20 = k[(1/4)/7] \n" ); document.write( "k = 28*20 = 560 \n" ); document.write( "----------------- \n" ); document.write( "Your Equation: \n" ); document.write( "m = 560[h/d] \n" ); document.write( "Substitute your given values of h= 3/4 of a house and d = 5 days \n" ); document.write( "to get: \n" ); document.write( "m = 560[(3/4)/5] \n" ); document.write( "m = 140*3/5 \n" ); document.write( "m = 28*3 \n" ); document.write( "m = 84 (# of men to complete 3/4 th of the house in 5 days) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |