document.write( "Question 128039: Five years ago a girl was one-half as old as her brother was then and now she is three years younger than he is. Find their present ages.\r
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document.write( "Please explain how you arrived at the answer... Much thanks!!!!! \n" );
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Algebra.Com's Answer #93803 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let x=\"girl's present age\" and y=\"brother's present age\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Five years ago a girl was one-half as old as her brother was then\" \n" ); document.write( "__ 2(x-5)=y-5 __ 2x-10=y-5 __ 2x-5=y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"now she is three years younger than he is\" __ x=y-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting __ x=(2x-5)-3 __ x=2x-8 __ x+8=2x \n" ); document.write( " |