document.write( "Question 19378: Zack is 2 years older than Jimmy. Last year Zack was 3 times as old as Jimmy. How is Zack now?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #9376 by MILIAJEY(4)\"\" \"About 
You can put this solution on YOUR website!
LET JIMMY BE X YEARS
\n" ); document.write( "THEN TODAY ZACK 'S AGE Y= X+2
\n" ); document.write( "ONE YEAR BACK AGE OF ZACK (Y-1)= 3(X-1)
\n" ); document.write( " = 3X -3
\n" ); document.write( " Y=3X-3 +1
\n" ); document.write( " = 3X -2
\n" ); document.write( "BUT Y= X + 2\r
\n" ); document.write( "\n" ); document.write( "X+ 2 = 3X -2\r
\n" ); document.write( "\n" ); document.write( " 4 = 3X-X
\n" ); document.write( " 4 = 2X
\n" ); document.write( " 2 = X
\n" ); document.write( " Y = 4
\n" ); document.write( "JIMMY IS 2 YRS OLD AND ZACK IS 4 YRS OLD.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );