document.write( "Question 128052: Solve for x:
\n" ); document.write( "logbase5(x+1)+logbase5(x-3)=1
\n" ); document.write( "

Algebra.Com's Answer #93756 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"log%285%2C%28x%2B1%29%29%2Blog%285%2C%28x-3%29%29=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First thing is to use the rule that \"log%28b%2Ca%29%2Blog%28b%2Cc%29=log%28b%2Cac%29\", so\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%285%2C%28x%2B1%29%28x-3%29%29=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Next, we note that if \"log%28b%2Ca%29=y\" then \"b%5Ey=x\", so\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%5E1=%28x%2B1%29%28x-3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5=x%5E2-2x-3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-8=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%28x%2B2%29=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=4\" or \"x=-2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "However, \"x=-2\" means that \"x-3%3C0\" and \"log%28b%2Cx%29\" is not defined for \"x%3C0\", therefore we need to exclude the second root.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The solution set consists of the single element 4.
\n" ); document.write( "
\n" );