document.write( "Question 127989: 2) Pipe A can fill a tank in 4hr. Pipe B can fill the tank in 9hr less than the time it takes pipe C, a drain pipe, to empty the tank. When all three pipes are open, it takes 2hr to fill the tank. How much time is required for pipe C to empty the tank if pipes A and B are closed? \n" ); document.write( "
Algebra.Com's Answer #93738 by ankor@dixie-net.com(22740)\"\" \"About 
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Pipe A can fill a tank in 4 hr. Pipe B can fill the tank in 9 hr less than the time it takes pipe C, a drain pipe, to empty the tank. When all three pipes are open, it takes 2 hr to fill the tank. How much time is required for pipe C to empty the tank if pipes A and B are closed?
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\n" ); document.write( "Pipe C's draining time = x (when Pipes A & B are closed)
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\n" ); document.write( "Pipes A's filling time = 4 hr (given)
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\n" ); document.write( "Pipe B's filling time = (x-9) (Given as 9 hrs less than C)
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\n" ); document.write( "Let the full tank = 1
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\n" ); document.write( "Filling is +, draining is -
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\n" ); document.write( "The equation when all three are open for 2 hrs:
\n" ); document.write( "\"2%2F4\" + \"2%2F%28%28x-9%29%29\" - \"2%2Fx\" = 1
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\n" ); document.write( "Multiply the equation by 4x(x-9) to get rid of the denominators:
\n" ); document.write( "4x(x-9)*\"2%2F4\" + 4x(x-9)*\"2%2F%28%28x-9%29%29\" - 4x(x-9)*\"2%2Fx\" = 4x(x-9)(1)
\n" ); document.write( "Cancel out the denominators and you have:\r
\n" ); document.write( "\n" ); document.write( "x(x-9)*2 + 4x(2) - 4(x-9)*2 = 4x(x-9)
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\n" ); document.write( "2x^2 - 18x + 8x - 8x + 72 = 4x^2 - 36x
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\n" ); document.write( "2x^2 - 4x^2 - 18x + 36x + 72 = 0
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\n" ); document.write( "-2x^2 - 18x + 72 = 0
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\n" ); document.write( "x^2 - 9x - 36 = 0; Divide by -2; simplifies and changes the signs
\n" ); document.write( "Factors to
\n" ); document.write( "(x + 3) (x - 12) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = 12 hrs for the the drain to empty the tank with A & B closed
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\n" ); document.write( "Check solution (B's fill time will be 12-9 = 3 hrs)
\n" ); document.write( "\"2%2F4\" + \"2%2F3\" - \"2%2F12\" =
\n" ); document.write( "\"6%2F12\" + \"8%2F12\" - \"2%2F12\" = \"12%2F12\" = 1
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