document.write( "Question 128001: A train leaves a city heading west and travels at 50 miles per hour. Three hours later, a second train leaves from the same place and travels in the same direction at 65 miles per hour. How long will it take for the second train to overtake the first train? \n" ); document.write( "
Algebra.Com's Answer #93729 by josmiceli(19441)\"\" \"About 
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I put a stopwatch on the 2 trains, but I wait until the moment
\n" ); document.write( "the 2nd train leaves. How far has the 1st train gone at that
\n" ); document.write( "point? \"50%2A3+=+150\" miles
\n" ); document.write( "Let \"t\" = elapsed time starting when 2nd train leaves
\n" ); document.write( "Let \"d\" = distance the 1st train has to travel to the point
\n" ); document.write( "where they meet
\n" ); document.write( "Then \"d+%2B+150\" is the distance the 2nd train has to travel
\n" ); document.write( "to get to their meeting point
\n" ); document.write( "\"d+=+50t\"
\n" ); document.write( "\"d+%2B+150+=+65t\"
\n" ); document.write( "Substitute \"d\" in the 1st equation for \"d\" in the 2nd
\n" ); document.write( "\"50t+%2B+150+=+65t\"
\n" ); document.write( "\"15t+=+150\"
\n" ); document.write( "\"t+=+10\" hrs
\n" ); document.write( "It will take the 2nd train 10 hours to overtake the 1st train
\n" ); document.write( "check:
\n" ); document.write( "\"d+=+50t\"
\n" ); document.write( "\"d+%2B+150+=+65t\"
\n" ); document.write( "-------------------
\n" ); document.write( "\"d+=+50%2A10\"
\n" ); document.write( "\"d+=+500\" mi
\n" ); document.write( "-------------------
\n" ); document.write( "\"d+%2B+150+=+65t\"
\n" ); document.write( "\"d+=+65%2A10+-+150\"
\n" ); document.write( "\"d+=+500\" mi
\n" ); document.write( "OK
\n" ); document.write( "
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