document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19323>Question 19323</A>: <I><SPAN STYLE=\"word-break: break-all;\">  How do I factor: z^2+25,  over the set of complex numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9370 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z^2+25=...since we are dealing with complex numbers we can write +25=-(25)*(-1)<BR>\n" );
document.write( "=-(5*5)(i*i)=-(5i)^2...so we have.... z^2+25 =z^2-(5i)^2<BR>\n" );
document.write( "using the formula (x+y)(x-y)=x^2-y^2..we get <BR>\n" );
document.write( "z^2-(5i)^2=(z+5i)(z-5i) </SPAN>\n" );
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