document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127932>Question 127932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i was doing my worksheet and this problem i got very very partial credit on, i started off with a lcd of 54... but i think i messed up my negatives somewhere ... please explain/show me...\r<BR>\n" );
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document.write( "(3g-1/9) - (g-1/6)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93698 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3g-(1/9)) - (g-(1/6)) <BR>\n" );
document.write( "=((27g-1)/9)-((6g-1)/6) LCD=54<BR>\n" );
document.write( "=((6(27g-1))-(9(6g-1)))/54<BR>\n" );
document.write( "=((162g-6)-(54g-9))/54<BR>\n" );
document.write( "=(162g-6-54g+9)/54<BR>\n" );
document.write( "=(108g+3)/54<BR>\n" );
document.write( "=2g+(3/54)<BR>\n" );
document.write( "=2g+(1/18)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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