document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127933>Question 127933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, Can I have some help finding the domain of the function?\r<BR>\n" );
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document.write( "k(x)=sqrt(x+3)/x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93697 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3<=x<1 U 1<x<infinity<BR>\n" );
document.write( "x can't be 1 because the denominator would be zero and we can't have division by zero.<BR>\n" );
document.write( "x can't be less than -3 because sqrt(x+3) would be an imaginary number.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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