document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19336>Question 19336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to solve an equation 18x=15x^2+12x  I worked it out as 18x-15x^2+12x = 3x(6-5x+4) I'm lost from here  I think the instructor meant for the problem to be 18x^3=15x^2+12x  This would make more sense to make it 3x(6x^2-5x+4)  Either way I cant seem to come up with the next step  I tried to use -8 & 3 but not sure how  Please help  Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9368 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm trying to solve an equation 18x=15x^2+12x  I worked it out as 18x-15x^2+12x = 3x(6-5x+4) I'm lost from here  I think the instructor meant for the problem to be 18x^3=15x^2+12x  This would make more sense to make it 3x(6x^2-5x+4)  Either way I cant seem to come up with the next step  I tried to use -8 & 3 but not sure how  Please help  Thank you<BR>\n" );
document.write( "18x=15x^2+12x  assuming this is ok<BR>\n" );
document.write( "15x^2+12x-18x=0<BR>\n" );
document.write( "15x^2-6x=0<BR>\n" );
document.write( "3x(5x-2)=0....ONCE YOU GOT THE EXPRESSION FACTORISED AND IF THE PRODUCT IS ZERO>>>THEN>>ONE OF THE FACTORS SHOULD BE ZERO>>>THAT IS THE SOLUTION>>><BR>\n" );
document.write( "hence 3x=0 or 5x-2=0<BR>\n" );
document.write( "so x=0 or 5x=2..or x=2/5<BR>\n" );
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