document.write( "Question 127841: use g(x)=5/(1-2x) and f(x)=1-x^2\r
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\n" ); document.write( "\n" ); document.write( "find f(-5)\r
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\n" ); document.write( "\n" ); document.write( "find the domain of g(x)
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Algebra.Com's Answer #93635 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
A word about function notation. f or g or h is a function. f(x) is the value of the function f at x, g(a) is the value of the function g at a. \r
\n" ); document.write( "\n" ); document.write( "If \"f%28x%29=1-x%5E2\", then \"1-x%5E2\" is the value of the function f at x, so f(-5) is the value of the function at -5, i.e. \"f%28-5%29=1-%28-5%29%5E2\". You do the arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "The domain of a function is the set of values for which the function is defined. The given function g is a rational expression that is defined everywhere except where the denominator is zero. So, if \"1-2x=0\", then g is not defined.\r
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\n" ); document.write( "\n" ); document.write( "\"1-2x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the domain of g is all real numbers except \"1%2F2\". In interval notation:\r
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\n" ); document.write( "\n" ); document.write( "(\"-infinity\",\"1%2F2\") U (\"1%2F2\",\"infinity\")\r
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\n" ); document.write( "\n" ); document.write( "In set notation {x|x is real, \"x%3C%3E1%2F2\"}\r
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