document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127817>Question 127817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a question I missed from a recent test.  I'm beating my head against the wall trying to figure this out.  Thanks in advance for any help you can provide.\r<BR>\n" );
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document.write( "How much of a 75% chemical solution must be mixed with a 25% solution to make 10 liters of a 40% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93619 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We want to end up with a 10 liters of 40% solution.  That means that of the 10 liters, 4 liters are the chemical, and the rest is something else.  To make this mixture, we want to mix x liters of 75% solution with enough 25% solution to make the full 10 liters.  So the amount of 25% solution must be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10-x ALIGN=MIDDLE  ALT=\"10-x\"   DISABLED_style= \"max-width:90%; height:auto;\" > liters.\r<BR>\n" );
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document.write( "The 75% solution has <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.75x ALIGN=MIDDLE  ALT=\".75x\"   DISABLED_style= \"max-width:90%; height:auto;\" > liters of chemical, and the 25% solution has <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.25%2810-x%29 ALIGN=MIDDLE  ALT=\".25%2810-x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > liters of chemical.  These two quantities must add up to the 4 liters that make up the amount of chemical in the final solution (geez, that sounds ominous!).\r<BR>\n" );
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document.write( "So:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.75x%2B.25%2810-x%29=4 ALIGN=MIDDLE  ALT=\".75x%2B.25%2810-x%29=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.75x-.25x%2B2.5=4 ALIGN=MIDDLE  ALT=\".75x-.25x%2B2.5=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.5x=4-2.5=1.5 ALIGN=MIDDLE  ALT=\".5x=4-2.5=1.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=3 ALIGN=MIDDLE  ALT=\"x=3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So there are 3 liters of 75% solution, meaning that there are 7 liters of 25% solution.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A.75=2.25 ALIGN=MIDDLE  ALT=\"3%2A.75=2.25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%2A.25=1.75 ALIGN=MIDDLE  ALT=\"7%2A.25=1.75\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.25%2B1.75=4 ALIGN=MIDDLE  ALT=\"2.25%2B1.75=4\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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