document.write( "Question 127779: Ernesto leaves Miami and travels toward Orlando at 60 mi/hr. An hour later Dick leaves Orlando and travels toward Miami at 50 mi/hr. If the two cities are 280 miles apart, how many hours will it take for Ernesto to meet Dick? \n" ); document.write( "
Algebra.Com's Answer #93605 by josmiceli(19441)\"\" \"About 
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The way I do this is to put a stopwatch on them
\n" ); document.write( "both at the moment Dick takes off and Ernesto
\n" ); document.write( "is already flying.
\n" ); document.write( "When Dick takes off, Ernesto has already gone
\n" ); document.write( "(distance = rate x time) \"60%2A1+=+60\"miles
\n" ); document.write( "Now start the stopwatch and let \"t\"=
\n" ); document.write( "the time elapsed until they meet. Note that
\n" ); document.write( "they are now \"280+-+60+=+220\"miles apart
\n" ); document.write( "\"50t+%2B+60t+=+280+-+60\"
\n" ); document.write( "\"110t+=+220\"
\n" ); document.write( "\"t+=+2\"hrs
\n" ); document.write( "Ernesto has been in the air for 1 hour, so
\n" ); document.write( "\"1+%2B+2+=+3\" and
\n" ); document.write( "It takes him 3 hours to meet Dick
\n" ); document.write( "
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