document.write( "Question 125353: Hi I need some help with evaluating this function.\r
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document.write( "f(x)=abs(x)/x;\r
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document.write( "f(-2),f(-1),f(0),f(5),f(x^2),f(1/x) \n" );
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Algebra.Com's Answer #93575 by HyperBrain(694)![]() ![]() ![]() You can put this solution on YOUR website! If x is negative, |x|=-x\r \n" ); document.write( "\n" ); document.write( "If x is zero or positive, |x|=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Evidence? \n" ); document.write( " \n" ); document.write( "There is a discontinuity at x=0. \n" ); document.write( " \n" ); document.write( "Please take note that if x is a real number then x^2 is always positive. \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( "IF x is positive, 1/x is positive \n" ); document.write( "If x is zero, 1/x is undefined \n" ); document.write( "If x is negative, 1/x is negative\r \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "If x is negative, \n" ); document.write( " \n" ); document.write( "If x is zero, \n" ); document.write( " \n" ); document.write( "If x is positive, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Please watch our video http://www.metacafe.com/watch/1101445/science_avenue/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Power up, \n" ); document.write( "HyperBrain! \n" ); document.write( " |