document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127711>Question 127711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can I have some help concerning functions?\r<BR>\n" );
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document.write( "A quadratic function is given.<BR>\n" );
document.write( "f(x) = x^2 - 9x<BR>\n" );
document.write( "(a) Express the quadratic function in standard form.<BR>\n" );
document.write( "f(x) = a(x - h)^2 + k where\r<BR>\n" );
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document.write( "a = <BR>\n" );
document.write( "h = <BR>\n" );
document.write( "k =  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93563 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to get the \"perfect square\" part of the function, divide the x coefficient by 2 and add the square of the result\r<BR>\n" );
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document.write( "since adding a quantity to the function would change the function, you must also subtract the same amount\r<BR>\n" );
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document.write( "f(x)=x^2-9x __ f(x)=x^2-9x+((-9/2)^2)-((-9/2)^2) __ f(x)=(x-(9/2))^2-((-9/2)^2)\r<BR>\n" );
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document.write( "a=1 __ h=9/2 __ k=-((-9/2)^2) </SPAN>\n" );
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