document.write( "Question 19320: 2x-3y+5z=-5, 2y-3z=4, and 4z=-8 \n" ); document.write( "
Algebra.Com's Answer #9355 by akmb1215(68)\"\" \"About 
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To start this problem, solve the third equation for z:\r
\n" ); document.write( "\n" ); document.write( "\"4z+=+-8\"
\n" ); document.write( "\"z+=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "Now, plug -2 in for z in the second equation to get:\r
\n" ); document.write( "\n" ); document.write( "\"2y+-+3%28-2%29+=+4\"
\n" ); document.write( "\"2y+%2B+6+=+4\"
\n" ); document.write( "\"2y+=+-2\"
\n" ); document.write( "\"y+=+-1\"\r
\n" ); document.write( "\n" ); document.write( "Finally, plug -2 in for z AND -1 in for y in the first equation and solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"2x+-+3%28-1%29+%2B+5%28-2%29+=+-5\"
\n" ); document.write( "\"2x+%2B+3+-+10+=+-5\"
\n" ); document.write( "\"2x+-+7+=+-5\"
\n" ); document.write( "\"2x+=+2\"
\n" ); document.write( "\"x+=+1\"\r
\n" ); document.write( "\n" ); document.write( "Your final answers would be x=1; y=-1; x=-2.
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