document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19326>Question 19326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle that is two-thirds of its supplement.<BR>\n" );
document.write( "A. 36 degree     B. 54 degree     C. 72 degree     D. 108 degree<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9354 by </B><A HREF=/tutors/aboutme.mpl?userid=mmm4444bot><B>mmm4444bot(95)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mmm4444bot><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello There:\r<BR>\n" );
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document.write( "First off, we need to know what the definition of a supplementary angle.\r<BR>\n" );
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document.write( "When you have an angle that is less than 180 degrees, then the supplement is the angle that gives you a total of 180 degrees if you add it to your angle.\r<BR>\n" );
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document.write( "Let me explain that in a different way with some examples.\r<BR>\n" );
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document.write( "If the angle is 100 degrees, then the supplement is 80 degrees because 100 + 80 = 180 degrees.\r<BR>\n" );
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document.write( "If the angle is 45 degrees, then the supplement is 135 degrees because 45 + 135 = 180 degrees.\r<BR>\n" );
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document.write( "In other words, if you're given an angle that is less than 180 degrees, you find that angle's supplement by subtracting it from 180 degrees.\r<BR>\n" );
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document.write( "Let choose the variable name x to represent our unknown angle.\r<BR>\n" );
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document.write( "If x is the angle, then 180 - x is the supplement.\r<BR>\n" );
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document.write( "Two-thirds of the supplement can be expressed as (2/3)*(180 - x).\r<BR>\n" );
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document.write( "(The asterisk means multiplication.)\r<BR>\n" );
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document.write( "This is enough information to write an equation.\r<BR>\n" );
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document.write( "x = (2/3)*(180 - x)\r<BR>\n" );
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document.write( "x = (2/3)*180 - (2/3)*x\r<BR>\n" );
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document.write( "x = 120 - (2/3)*x\r<BR>\n" );
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document.write( "x + (2/3)*x = 120\r<BR>\n" );
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document.write( "(5/3)*x = 120\r<BR>\n" );
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document.write( "x = (3/5)*120\r<BR>\n" );
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document.write( "x = 72\r<BR>\n" );
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document.write( "Let's check our result.\r<BR>\n" );
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document.write( "The supplement to 72 degrees is 180 - 72 = 108 degrees.  Two-thirds of 108 is 72.  Our result checks out.\r<BR>\n" );
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document.write( "The answer is 72 degrees.\r<BR>\n" );
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document.write( "~ Mark<BR>\n" );
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