document.write( "Question 127657: Translate the following statement into an algebraic equation. Let y represent the number.
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document.write( "6 times a number is 14 more than that number
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document.write( "A. 6y + 14 = y
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document.write( "B. 6 = 14y + y
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document.write( "C. 6y = x + 14
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document.write( "D. 6y = 14y
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document.write( " I chose D but was not sure \n" );
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Algebra.Com's Answer #93539 by bucky(2189) ![]() You can put this solution on YOUR website! No wonder you aren't sure which answer is correct. The correct answer is not in this list \n" ); document.write( "unless you made a keyboarding mistake in answer C. \n" ); document.write( ". \n" ); document.write( "6 times a number is 6y \n" ); document.write( ". \n" ); document.write( "then \"is\" means \"equals\" \n" ); document.write( ". \n" ); document.write( "14 more than the number is y + 14 \n" ); document.write( ". \n" ); document.write( "Put this all together and the answer is: \n" ); document.write( ". \n" ); document.write( "6y = y + 14 \n" ); document.write( ". \n" ); document.write( "That's the correct answer. It would be answer C except that C says \n" ); document.write( ". \n" ); document.write( "6y = x + 14 \n" ); document.write( ". \n" ); document.write( "If the x in answer C were changed to y then answer C would be correct. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |