document.write( "Question 127638This question is from textbook algebra and trigonometry with analiytic geometry
\n" ); document.write( ": A hot-air balloon is released at 1:00 P.M. and rises vertically at a rate of 4 meters/sec . An observation point is situated at 125 meters from a point on the ground directly below the balloon (see the figure). If t denotes the time (in seconds) after 1:00 P.M., express the distance d between the balloon and the observation point as a function of t.\r
\n" ); document.write( "\n" ); document.write( "Please use the notation \"sqr(a)\" which equals PLEASE PLEASE, HELP
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Algebra.Com's Answer #93530 by josmiceli(19441)\"\" \"About 
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The observation point, the point directly below and the
\n" ); document.write( "height of the ballon form a right triangle. The distance
\n" ); document.write( "from the observer to the ballon is the hypotenuse
\n" ); document.write( "\"d+=+sqrt%28h%5E2+%2B+125%5E2%29\"where distances are in meters
\n" ); document.write( "The ballon is going up at a rate of 4 m/sec. If \"t\"
\n" ); document.write( "is the elapsed time, \"h+=+4t\"where \"t\"is in seconds
\n" ); document.write( "and \"h\" is in meters.
\n" ); document.write( "\"d+=+sqrt%28%284t%29%5E2+%2B+125%5E2%29\"
\n" ); document.write( "\"d+=+sqrt%2816t%5E2+%2B+15625%29\" meters answer
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