document.write( "Question 127638This question is from textbook algebra and trigonometry with analiytic geometry
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document.write( ": A hot-air balloon is released at 1:00 P.M. and rises vertically at a rate of 4 meters/sec . An observation point is situated at 125 meters from a point on the ground directly below the balloon (see the figure). If t denotes the time (in seconds) after 1:00 P.M., express the distance d between the balloon and the observation point as a function of t.\r
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document.write( "Please use the notation \"sqr(a)\" which equals PLEASE PLEASE, HELP \n" );
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Algebra.Com's Answer #93530 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The observation point, the point directly below and the \n" ); document.write( "height of the ballon form a right triangle. The distance \n" ); document.write( "from the observer to the ballon is the hypotenuse \n" ); document.write( " \n" ); document.write( "The ballon is going up at a rate of 4 m/sec. If \n" ); document.write( "is the elapsed time, \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " |