document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19333>Question 19333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(x-6)+6=5(x+2)-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9353 by </B><A HREF=/tutors/aboutme.mpl?userid=mmm4444bot><B>mmm4444bot(95)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mmm4444bot><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello There:\r<BR>\n" );
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document.write( "3*(x - 6) + 6 = 5*(x + 2) - 12\r<BR>\n" );
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document.write( "(The asterisks mean multiplication.)\r<BR>\n" );
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document.write( "Start by using the distributive property to get rid of the parentheses.\r<BR>\n" );
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document.write( "3*(x - 6) means that both the x and the -6 inside of the parentheses gets multiplied by 3.  Likewise, both the x and the 2 get multiplied by 5 on the other set of parentheses.\r<BR>\n" );
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document.write( "3*x - 18 + 6 = 5*x + 10 - 12\r<BR>\n" );
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document.write( "Do the arithmetic on each side to add the constants together.\r<BR>\n" );
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document.write( "3*x - 12 = 5*x - 2\r<BR>\n" );
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document.write( "Next, we want all of the x-terms to be on one side of the equals sign and the constants on the other side.\r<BR>\n" );
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document.write( "Let's subtract 3*x from both sides.\r<BR>\n" );
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document.write( "3*x - 3*x - 12 = 5*x - 3*x - 2\r<BR>\n" );
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document.write( "-12 = 2*x - 2\r<BR>\n" );
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document.write( "Add 2 to each side.\r<BR>\n" );
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document.write( "2 - 12 = 2*x = 2 - 2\r<BR>\n" );
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document.write( "-10 = 2*x\r<BR>\n" );
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document.write( "Divide both sides by 2 to solve for x.\r<BR>\n" );
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document.write( "-10/2 = (2/2)*x\r<BR>\n" );
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document.write( "x = -5\r<BR>\n" );
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document.write( "Let's check our result.  We will substitute -5 for x into the original equation and simplify by doing the arithmetic to see if we end up with a true statement.\r<BR>\n" );
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document.write( "3*(x - 6) + 6 = 5*(x + 2) - 12\r<BR>\n" );
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document.write( "3*(-5 - 6) + 6 = 5*(-5 + 2) - 12\r<BR>\n" );
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document.write( "3*(-11) + 6 = 5*(-3) - 12\r<BR>\n" );
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document.write( "-33 + 6 = -15 - 12\r<BR>\n" );
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document.write( "-27 = -27\r<BR>\n" );
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document.write( "This is a true statement, so our solution is correct.\r<BR>\n" );
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document.write( "~ Mark<BR>\n" );
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