document.write( "Question 127588: suppose that a supermarket sells cashews for 4.50 per pound and pecans for 6.50 a pound how many pounds of each are needed to obtain a mixture of 40lbs that can be sold for 5.85 per pound \n" ); document.write( "

Algebra.Com's Answer #93526 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
(price/lb cashews)x(lbs cashews) + (price/lb pecans)x(lbs pecans)
\n" ); document.write( "divided by (lbs of cashews and pecans)
\n" ); document.write( "= (price per lb of mixture)
\n" ); document.write( "Let $\"c\"$ = pounds of cashews needed
\n" ); document.write( "Let $\"p\"$ = pounds of pecans needed
\n" ); document.write( " $\"%284.5c+%2B+6.5p%29+%2F+%28p+%2B+c%29+=+5.85\"$
\n" ); document.write( " $\"c+%2B+p+=+40\"$
\n" ); document.write( " $\"p+=+40+-+c\"$
\n" ); document.write( " $\"%284.5c+%2B+6.5p%29+%2F+%28p+%2B+c%29+=+5.85\"$
\n" ); document.write( " $\"%284.5c+%2B+6.5%2840+-+c%29%29+%2F+40+=+5.85\"$
\n" ); document.write( " $\"4.5c+%2B+260+-+6.5c+=+40%2A5.85\"$
\n" ); document.write( " $\"-2c+=+234+-+260\"$
\n" ); document.write( " $\"-2c+=+-26\"$
\n" ); document.write( " $\"c+=+13\"$
\n" ); document.write( " $\"p+=+40+-+c\"$
\n" ); document.write( " $\"p+=+27\"$
\n" ); document.write( "13 pounds of cashews and 27 pounds of pecans are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"%284.5c+%2B+6.5p%29+%2F+40+=+5.85\"$
\n" ); document.write( " $\"%284.5%2A13+%2B+6.5%2A27%29+%2F+40+=+5.85\"$
\n" ); document.write( " $\"%2858.5+%2B+175.5%29+%2F+40+=+5.85\"$
\n" ); document.write( " $\"234%2F40+=+5.85\"$
\n" ); document.write( " $\"234+=+5.85%2A40\"$
\n" ); document.write( " $\"234+=+234\"$ \r
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