document.write( "Question 127634: Hello, I have a few problems, and this should be easy but I'm over thinking it.
\n" ); document.write( "f9x0 = x/x+t g(x)= x^3\r
\n" ); document.write( "\n" ); document.write( "A) Find f(x) + g(x)
\n" ); document.write( "I found a common denominator, (x+1) but I got confused after that...
\n" ); document.write( "x^3 is really X^3/1 so to get the common denominator, would you multiply by x since the one is already in the denominator or just by x? and what about the denominator?\r
\n" ); document.write( "\n" ); document.write( "Also, I have a function:
\n" ); document.write( "f(x)= cube root of (x-1) g(x)= x^3 + 1\r
\n" ); document.write( "\n" ); document.write( "c) f(f(x)=?
\n" ); document.write( "All you have to do is substitute for this problem, correct?
\n" ); document.write( "So... f(f(x))= {cube root[cube root of (x-1)] -1} Would be correct?\r
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\n" ); document.write( "\n" ); document.write( "If anyone could set me straight with these, I'd appreciate it!
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Algebra.Com's Answer #93520 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+x%2F%28x%2Bt%29\" \"g%28x%29=+x%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "Is the denominator \"x%2Bt\" or \"x%2B1\"? I'm going to assume a typo in the original function statement since you go on about \"x%2B1\".\r
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\n" ); document.write( "\n" ); document.write( "The two denominators are \"x%2B1\" and \"1\". Since they have no factors in common, the common denominator is the product of the two: \"%28x%2B1%29%281%29=x%2B1\",\r
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\n" ); document.write( "\n" ); document.write( "So:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2F%28x%2B1%29%29%2B%28x%5E3%29%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B%28x%5E3%28x%2B1%29%29%29%2F%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E4%2Bx%5E3%2Bx%29%2F%28x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28f%28x%29%29=+root%283%2Croot%283%2Cx-1%29%29+-1\" is your answer...but you missed it by THAT much.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28f%28x%29%29=+root%283%2Croot%283%2Cx-1%29-1%29\". See the difference? You just had a misplaced bracket.
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