document.write( "Question 127634: Hello, I have a few problems, and this should be easy but I'm over thinking it.
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document.write( "f9x0 = x/x+t g(x)= x^3\r
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document.write( "A) Find f(x) + g(x)
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document.write( "I found a common denominator, (x+1) but I got confused after that...
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document.write( "x^3 is really X^3/1 so to get the common denominator, would you multiply by x since the one is already in the denominator or just by x? and what about the denominator?\r
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document.write( "Also, I have a function:
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document.write( "f(x)= cube root of (x-1) g(x)= x^3 + 1\r
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document.write( "c) f(f(x)=?
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document.write( "All you have to do is substitute for this problem, correct?
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document.write( "So... f(f(x))= {cube root[cube root of (x-1)] -1} Would be correct?\r
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document.write( "If anyone could set me straight with these, I'd appreciate it! \n" );
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Algebra.Com's Answer #93520 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is the denominator \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The two denominators are \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |