document.write( "Question 127562This question is from textbook
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document.write( ": 1 If a number is added to the numerator of 3/4 and twice as much is added to the denominator, the result is 4/7. Find the number.\r
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document.write( "2. The sum of a number an its reciprocal is 13/6. Find the numbers.\r
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document.write( "3. An inlet pipe can fill an empty swimming pool in 5 hours, and another inlet pipe can fill the pool in 4 hours . How long will it take both pipes to fill the pool? \n" );
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Algebra.Com's Answer #93517 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If a number is added to the numerator of 3/4 and twice as much is added to the denominator, the result is 4/7. Find the number. \n" ); document.write( ": \n" ); document.write( "Let the number to be added = x \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply, and solve for x \n" ); document.write( "4(2x+7) = 7(x+3) \n" ); document.write( "8x + 28 = 7x + 21 \n" ); document.write( "8x - 7x = 21 - 28 \n" ); document.write( "x = -7 \n" ); document.write( ": \n" ); document.write( "Check solution in original equation, substitute -7 for x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "2. The sum of a number an its reciprocal is 13/6. Find the numbers. \n" ); document.write( "x + \n" ); document.write( "Multiply equation by 6x to get rid of the denominators \n" ); document.write( "6x(x) + 6x* \n" ); document.write( "6x^2 + 6 = 13x \n" ); document.write( ": \n" ); document.write( "6x^2 - 13x + 6 = 0; a quadratic equation \n" ); document.write( ": \n" ); document.write( "After a little slogging, we find we can factor this to: \n" ); document.write( "(2x - 3)(3x - 2) = 0 \n" ); document.write( ": \n" ); document.write( "2x = 3 \n" ); document.write( "x = \n" ); document.write( "and \n" ); document.write( "3x = 2 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Check solution using x = 3/2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Note that the 2nd solution is the reciprocal of the 1st \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3. An inlet pipe can fill an empty swimming pool in 5 hours, and another inlet pipe can fill the pool in 4 hours . How long will it take both pipes to fill the pool? \n" ); document.write( ": \n" ); document.write( "A typical shared work problem: \n" ); document.write( "Let t = time required when both pipes are open \n" ); document.write( "Let the full pool = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by a common multiple, 20 will work \n" ); document.write( "20* \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( "4t + 5t = 20 \n" ); document.write( ": \n" ); document.write( "9t = 20 \n" ); document.write( "t = \n" ); document.write( "t = 2.22 hrs or 2 hrs & 13.3 min \n" ); document.write( ": \n" ); document.write( "Check solution using 2.22 for t: \n" ); document.write( " \n" ); document.write( ".444 + .555 = .999 ~ 1; confirms our solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Could you follow the procedures in all these problems? Let me know if you have any questions \n" ); document.write( " \n" ); document.write( " |