document.write( "Question 127623: This problem is not from my textbook it is a worksheet problem.
\n" ); document.write( "Use Descartes’s rule of signs to discuss the possibilities for the roots of the equation.
\n" ); document.write( "4x3-9x2+2x+3=0
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Algebra.Com's Answer #93505 by solver91311(24713)\"\" \"About 
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\"4x%5E3-9x%5E2%2B2x%2B3=0\"\r
\n" ); document.write( "\n" ); document.write( "The signs are + - + +. So there are 2 sign changes, 1st term to 2nd term, and 2nd term to 3rd term.\r
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\n" ); document.write( "\n" ); document.write( "Two sign changes means that there are at most 2 positive roots. There could also be 0 positive roots.\r
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\n" ); document.write( "\n" ); document.write( "Evaluate \"f%28-x%29\"
\n" ); document.write( "\"4%28-x%29%5E3-9%28-x%29%5E2%2B2%28-x%29%2B3=0\"
\n" ); document.write( "\"-4x%5E3-9x%5E2-2x%2B3=0\"\r
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\n" ); document.write( "\n" ); document.write( "The signs are - - - +. So there is 1 sign change from the 3rd to the 4th term.\r
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\n" ); document.write( "\n" ); document.write( "One sign change on \"f%28-x%29\" means that there is exactly 1 negative real root.\r
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\n" ); document.write( "\n" ); document.write( "So overall, this equation has either 2 positive real roots and 1 negative real root, or a conjugate pair of complex roots and 1 negative real root.\r
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\n" ); document.write( "\n" ); document.write( "A graph of the function demonstrates that the first possibility is the actual case.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C5%2C-5%2C5%2C4x%5E3-9x%5E2%2B2x%2B3%29\"
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