document.write( "Question 127609This question is from textbook College Algebra
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document.write( ": b^2/b^2-4 - 4/b^2-2b
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document.write( "I know you have to find the common denominators by factoring the denominators so it ends up being:
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document.write( "b^2/(b-2)(b+2) - 4/(b-2)(b+b) but after that step, I don't know what to do and which numbers to pick to get the same denominator. \n" );
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Algebra.Com's Answer #93503 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First of all you have a mistake \n" ); document.write( "b^2/b^2-4 - 4/b^2-2b =b^2/(b-2)(b+2) - 4/(b-2)(b)\r \n" ); document.write( "\n" ); document.write( "the denominators are (b-2)(b+2) and (b-2)(b) to find the common denominator \n" ); document.write( "you have to select (b-2) (because is in both denominators) and (b+2) and (b)\r \n" ); document.write( "\n" ); document.write( "so the common denominator is (b-2)(b+2)b \n" ); document.write( " |