document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=127531>Question 127531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 25% acid solution must be mixed with  100 gallons of a 6% acid solution to obtain a solution that is 20% acid?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #93468 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=93468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 25% acid solution must be mixed with  100 gallons of a 6% acid solution to obtain a solution that is 20% acid?<BR>\n" );
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document.write( "25% solution DATA;<BR>\n" );
document.write( "Amount = x gallons ; amt. of active ingredient = 0.25x gallons<BR>\n" );
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document.write( "6% solution DATA;<BR>\n" );
document.write( "Amount = 100 gallons ; amt. of active = 0.06*100 = 6 gallons<BR>\n" );
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document.write( "Mixture DATA:<BR>\n" );
document.write( "Amt. = 100+x gallons ; amt of active = 0.20(100+x)= 20 + 0.20x gallons<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.25x + 6 = 20+0.20x<BR>\n" );
document.write( "0.05x = 14 <BR>\n" );
document.write( "x = 280 gallons (amt of 25% solution needed for the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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