document.write( "Question 127528: what is the square root of
\n" ); document.write( "a^2-10a+25
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Algebra.Com's Answer #93460 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"a%5E2+-+10a+%2B+25\"
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\n" ); document.write( "You can tell this is a perfect square trinomial by dividing the multiplier of the \"a\" term
\n" ); document.write( "by 2 and then squaring it. If the answer is +25 then the given trinomial is a perfect square.
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\n" ); document.write( "In this problem you divide the -10 by 2 to get -5 and when you square -5 you get +25 ... just
\n" ); document.write( "as the problem already has. So the given trinomial is a perfect square.
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\n" ); document.write( "And the two factors will have half of -10 as their numerical part.
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\n" ); document.write( "So we can write:
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\n" ); document.write( "\"a%5E2+-+10a+%2B+25+=+%28a+-5%29%2A%28a+-+5%29+=+%28a-5%29%5E2\"
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\n" ); document.write( "Therefore, the square root of the given trinomial is the square root of:
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\n" ); document.write( "\"%28a+-+5%29%5E2\"
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\n" ); document.write( "and when you take the square root of this quantity, the answer is just:
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\n" ); document.write( "\"a+-+5\"
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\n" ); document.write( "That's the answer to your problem. Hope this helps you to see a way to get this answer.
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