document.write( "Question 127484: Solve the system of inequalities by graphing:
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document.write( "2x + y < 6
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document.write( "y > 1
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Algebra.Com's Answer #93439 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Start with the given system of inequalities\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order to graph this system of inequalities, we need to graph each inequality one at a time.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First lets graph the first inequality \n" ); document.write( "\n" ); document.write( "In order to graph \n" ); document.write( "So lets graph the line \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute (0,0) into the inequality\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of Firefox to see these images.)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since this inequality is true, we simply shade the entire region that contains (0,0)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "(note: since the inequality contains a less-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)\r \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now lets graph the second inequality \n" ); document.write( "\n" ); document.write( "In order to graph \n" ); document.write( "So lets graph the line \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute (0,0) into the inequality\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "(note: since the inequality contains a greater-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)\r \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we essentially have these 2 regions:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Region #1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Region #2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When these inequalities are graphed on the same coordinate system, the regions overlap to produce this region. It's a little hard to see, but after evenly shading each region, the intersecting region will be the most shaded in. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is a cleaner look at the intersection of regions\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |