document.write( "Question 127486: I got stuck on this problem here: When Jim cleaned out the fountain in front of the mayor's house, he found 20 nickels and quarters. The mixture of coins totaled up to $2.60. How many quarters did Jim find? \r
\n" ); document.write( "\n" ); document.write( "Thanks in advance!
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Algebra.Com's Answer #93405 by Earlsdon(6294)\"\" \"About 
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Let N = the number of nickels and Q = the number of quarters.
\n" ); document.write( "Then:
\n" ); document.write( "\"N%2BQ+=+20\" This is the total number of coins.
\n" ); document.write( "The value of N nickels is just \"0.05N\"
\n" ); document.write( "and the value of Q quarters is just \"0.25Q\" and the sum of these is $2.60
\n" ); document.write( "So now we have two equations:
\n" ); document.write( "\"N%2BQ+=+20\" Rewrite this as: \"N+=+20-Q\" and substitute in the equation below:
\n" ); document.write( "\"0.05N%2B0.25Q+=+2.60\"
\n" ); document.write( "\"0.05%2820-Q%29%2B0.25Q+=+2.60\" Simplify and combine like-terms.
\n" ); document.write( "\"1-0.05Q%2B0.25Q+=+2.60\"
\n" ); document.write( "\"1%2B0.2Q+=+2.60\" Subtract 1 from both sides.
\n" ); document.write( "\"0.2Q+=+1.6\" Divide both sides by 0.2
\n" ); document.write( "\"Q+=+8\"
\n" ); document.write( "Jim found 8 quarters.
\n" ); document.write( "Check:
\n" ); document.write( "\"0.05N%2B0.25Q+=+2.60\" Substitute Q = 8 and N = 20-8 = 12.
\n" ); document.write( "\"0.05%2812%29%2B0.25%288%29+=+2.60\"
\n" ); document.write( "\"0.60%2B2.00+=+2.60\"
\n" ); document.write( "\"2.60+=+2.60\"
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