document.write( "Question 127449: Ellen wishes to mix candy worth $1.56 per pound with candy worth $2.60 per pound to form 20 pounds of a mixture worth $2.29 per pound. How many pounds of the more expensive candy should she use? \n" ); document.write( "
Algebra.Com's Answer #93378 by checkley71(8403)\"\" \"About 
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2.6x+1.56(20-x)=2.29*20
\n" ); document.write( "2.6x+31.2-1.56x=45.8
\n" ); document.write( "1.04x=45.8-31.2
\n" ); document.write( "1.04x=14.6
\n" ); document.write( "x=14.6/1.04
\n" ); document.write( "x=14.04 pounds of the expensive candy is required.
\n" ); document.write( "PROOF:
\n" ); document.write( "2.6*14.04+1.56(20-14.04)=45.8
\n" ); document.write( "36.50+1.56*5.96=45.8
\n" ); document.write( "36.50+9.30=45.8
\n" ); document.write( "45.8=45.8
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