document.write( "Question 127449: Ellen wishes to mix candy worth $1.56 per pound with candy worth $2.60 per pound to form 20 pounds of a mixture worth $2.29 per pound. How many pounds of the more expensive candy should she use? \n" ); document.write( "
Algebra.Com's Answer #93378 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2.6x+1.56(20-x)=2.29*20 \n" ); document.write( "2.6x+31.2-1.56x=45.8 \n" ); document.write( "1.04x=45.8-31.2 \n" ); document.write( "1.04x=14.6 \n" ); document.write( "x=14.6/1.04 \n" ); document.write( "x=14.04 pounds of the expensive candy is required. \n" ); document.write( "PROOF: \n" ); document.write( "2.6*14.04+1.56(20-14.04)=45.8 \n" ); document.write( "36.50+1.56*5.96=45.8 \n" ); document.write( "36.50+9.30=45.8 \n" ); document.write( "45.8=45.8 \n" ); document.write( " |