document.write( "Question 127441: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 26 in., find the width of the rectangle. I have four choices (4 in, 5 in, 6 in, or 3 in.). I came up with 6 inches but this doesn't feel right. Is this correct? Thanks so much. \n" ); document.write( "

Algebra.Com's Answer #93362 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the width be W and the length be L.
\n" ); document.write( "The perimeter of a rectangle is given by:
\n" ); document.write( " $\"P+=+2L%2B2W\"$ and this, you are told, is 26 inches.
\n" ); document.write( "You also know that the length L is 1 more than twice the width, W, so you can write:
\n" ); document.write( " $\"L+=+2W%2B1\"$ Now substitute this into the formula for the perimeter to get:
\n" ); document.write( " $\"26+=+2%282W%2B1%29%2B2W\"$ Simplify and solve for W.
\n" ); document.write( " $\"26+=+4W%2B2%2B2W\"$
\n" ); document.write( " $\"26+=+6W%2B2\"$ Subtract 2 from both sides.
\n" ); document.write( " $\"24+=+6W\"$ Divide both sides by 6.
\n" ); document.write( " $\"4+=+W\"$
\n" ); document.write( "The width is 4 inches.
\n" ); document.write( "Check:
\n" ); document.write( " $\"P+=+2L%2B2W\"$
\n" ); document.write( " $\"P+=+2%282W%2B1%29%2B2W\"$ Substitute W = 4.
\n" ); document.write( " $\"P+=+2%282%284%29%2B1%29%2B2%284%29\"$
\n" ); document.write( " $\"P+=+2%289%29%2B8\"$
\n" ); document.write( " $\"P+=+18+%2B+8\"$
\n" ); document.write( " $\"P+=+26\"$ It checks! \n" ); document.write( "

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