document.write( "Question 127409: Can someone please help me solve this problem?\r
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document.write( "q+9/2 + q-3/3=6\r
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #93359 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "We can get rid of the denominators by multiplying the equation by 6: \n" ); document.write( "6* \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( "3(q+9) + 2(q-3) = 36 \n" ); document.write( ": \n" ); document.write( "3q + 27 + 2q - 6 = 36 \n" ); document.write( ": \n" ); document.write( "5q + 21 = 36 \n" ); document.write( ": \n" ); document.write( "5q = 36 - 21 \n" ); document.write( ": \n" ); document.write( "5q = 15 \n" ); document.write( "q = \n" ); document.write( "q = 3 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check in original equation, substitute 3 for q: \n" ); document.write( " \n" ); document.write( " |