document.write( "Question 127382: Solve.\r
\n" ); document.write( "\n" ); document.write( "3 - a-1/a+2 = a^2-1/a+2\r
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\n" ); document.write( "\n" ); document.write( "The first number seems to throwing me off, can someone help?
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Algebra.Com's Answer #93353 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume it's
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\n" ); document.write( "\"3+-+%28%28a-1%29%29%2F%28%28a%2B2%29%29+=+%28%28a%5E2-1%29%29%2F%28%28a%2B2%29%29\"
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\n" ); document.write( "\"3+=+%28%28a-1%29%29%2F%28%28a%2B2%29%29+%2B+%28%28a%5E2-1%29%29%2F%28%28a%2B2%29%29\"; Added \"%28%28a-1%29%29%2F%28%28a%2B2%29%29\" to both sides
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\n" ); document.write( "They have the same denominators so we can just write it:
\n" ); document.write( "\"3+=+%28%28+a+-+1+%2B+a%5E2+-+1%29%29%2F%28%28a%2B2%29%29\" = \"3+=+%28%28a%5E2+%2B+a+-+2%29%29%2F%28%28a%2B2%29%29\"; combine like terms, we have quadratic now
\n" ); document.write( "That will factor to:
\n" ); document.write( "\"3+=+%28%28a-1%29%28a%2B2%29%29%2F%28%28a%2B2%29%29\"
\n" ); document.write( "Cancel out the (a+2)'s and we have a simple equation
\n" ); document.write( "a - 1 = 3
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\n" ); document.write( "a = 3 + 1
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\n" ); document.write( "a = 4
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\n" ); document.write( "Check solution in the original equation, substitute 4 for a
\n" ); document.write( "\"3+-+%28%284-1%29%29%2F%28%284%2B2%29%29+=+%28%284%5E2-1%29%29%2F%28%284%2B2%29%29\"
\n" ); document.write( "\"3+-+%283%29%2F%286%29+=+%28%2816-1%29%29%2F%286%29\"
\n" ); document.write( "\"3+-+%283%29%2F%286%29+=+%2815%29%2F%286%29\"
\n" ); document.write( "3 is equal to 18/6:
\n" ); document.write( "\"18%2F6+-+%283%29%2F%286%29+=+%2815%29%2F%286%29\"; confirms our solution of a = 4\r
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\n" ); document.write( "Could you follow what we did here? Any questions?
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