document.write( "Question 127414: FIND AN EQUATION OF THE LINE CONTAINING THE POINT (-4,3) AND PARALLEL TO THE LINE 5x-3y=12. \n" ); document.write( "
Algebra.Com's Answer #93351 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First convert the standard equation \"5x-3y=12\" into slope intercept form\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"5x-3y=12\" Start with the given equation


\"5x-3y-5x=12-5x\" Subtract 5x from both sides


\"-3y=-5x%2B12\" Simplify


\"%28-3y%29%2F%28-3%29=%28-5x%2B12%29%2F%28-3%29\" Divide both sides by -3 to isolate y


\"y+=+%28-5x%29%2F%28-3%29%2B%2812%29%2F%28-3%29\" Break up the fraction on the right hand side


\"y+=+%285%2F3%29x-4\" Reduce and simplify


The original equation \"5x-3y=12\" (standard form) is equivalent to \"y+=+%285%2F3%29x-4\" (slope-intercept form)


The equation \"y+=+%285%2F3%29x-4\" is in the form \"y=mx%2Bb\" where \"m=5%2F3\" is the slope and \"b=-4\" is the y intercept.



\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's find the equation of the line that is parallel to \"y=%285%2F3%29x-4\" which goes through (-4,3)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

\n" ); document.write( "
\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"5%2F3\" (its from the slope of \"y=%285%2F3%29%2Ax-4\" which is also \"5%2F3\").\n" ); document.write( "Also since the unknown line goes through (-4,3), we can find the equation by plugging in this info into the point-slope formula
\n" ); document.write( "
\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y-3=%285%2F3%29%2A%28x%2B4%29\" Plug in \"m=5%2F3\", \"x%5B1%5D=-4\", and \"y%5B1%5D=3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y-3=%285%2F3%29%2Ax-%285%2F3%29%28-4%29\" Distribute \"5%2F3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y-3=%285%2F3%29%2Ax%2B20%2F3\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=%285%2F3%29%2Ax%2B20%2F3%2B3\"Add \"3\" to both sides to isolate y
\n" ); document.write( "
\n" ); document.write( " \"y=%285%2F3%29%2Ax%2B20%2F3%2B9%2F3\" Make into equivalent fractions with equal denominators
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=%285%2F3%29%2Ax%2B29%2F3\" Combine the fractions
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=%285%2F3%29%2Ax%2B29%2F3\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " So the equation of the line that is parallel to \"y=%285%2F3%29%2Ax-4\" and goes through (\"-4\",\"3\") is \"y=%285%2F3%29%2Ax%2B29%2F3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So here are the graphs of the equations \"y=%285%2F3%29%2Ax-4\" and \"y=%285%2F3%29%2Ax%2B29%2F3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%285%2F3%29%2Ax-4\" (red) and graph of the line \"y=%285%2F3%29%2Ax%2B29%2F3\"(green) that is parallel to the given graph and goes through (\"-4\",\"3\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );