document.write( "Question 127367: can you please help me solve this problem step by step. This is linear inequalities probelm 5(x+1)<3x+4 =\r
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Algebra.Com's Answer #93326 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"5%28x%2B1%29%3C3x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Solve inequalities the same way you solve equations, with two important exceptions. First, if you multiply or divide both sides of the inequality by a negative number, you must reverse the sense of the inequality.\r
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\n" ); document.write( "\n" ); document.write( "For example, we know it is true that \"-2%3C1\", but if we multiply both sides of the inequality by -1, we get 2 on the left and -1 on the right. The 'less than' symbol is no longer correct, it must be changed to 'greater than' because \"2%3E-1\"\r
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\n" ); document.write( "\n" ); document.write( "The second exception is that the solution set will be represented by an interval rather than a single value.\r
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\n" ); document.write( "\n" ); document.write( "\"5%28x%2B1%29%3C3x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute and remove parentheses
\n" ); document.write( "\"5x%2B5%3C3x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Add -3x to both sides
\n" ); document.write( "\"5x-3x%2B5%3C4\"
\n" ); document.write( "\"2x%2B5%3C4\"\r
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\n" ); document.write( "\n" ); document.write( "Add -5 to both sides
\n" ); document.write( "\"2x%3C4-5\"
\n" ); document.write( "\"2x%3C-1\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, divide both sides by 2
\n" ); document.write( "\"x%3C-1%2F2\" and the solution set is {x| x is real, \"x%3C-1%2F2\"}. You can also use interval notation (\"-infinity\",\"-1%2F2\"). Note the parentheses around the interval. Had the problem included the possiblity of equality, i.e. had it been \"5%28x%2B1%29%3C=3x%2B4\", then the interval would have been denoted by
\n" ); document.write( "(\"-infinity\",\"-1%2F2\"]. \r
\n" ); document.write( "\n" ); document.write( "Since we never multiplied or divided by a number that is <0, the sense of the inequality remains as it was in the original inequality.
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