document.write( "Question 127362: Frida is five years older than Fredelyn. In three years the product of her age and Fredelyn's age five years ago will be 9o years. zFind their present ages. \n" ); document.write( "
Algebra.Com's Answer #93316 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Frida's current age is x and Fredelyn's current age is y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The first thing we know is that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three years from now Frida will be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the expression for x in terms of y from the first equation into the second equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify, expand, and put into standard form: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From equation 1: Frida is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( " |