document.write( "Question 127355This question is from textbook
\n" ); document.write( ": How many liters (L) of a 30% ACID SOLUTION MUST BE ADDED TO 8 L of an 55% acid solution to obtain a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #93308 by josmiceli(19441)\"\" \"About 
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Let \"a\" = amount of 30% acid solution needed
\n" ); document.write( "Let \"b\" = amount of 55% acid solution
\n" ); document.write( "Given is \"b+=+8\"liters
\n" ); document.write( "(acid in 30% and 55% solutions)/(total solution) = 40%
\n" ); document.write( "\"%28.3a+%2B+.55b%29+%2F+%28a+%2B+b%29+=+.4\"
\n" ); document.write( "\"%28.3a+%2B+.55%2A8%29+%2F+%28a+%2B+8%29+=+.4\"
\n" ); document.write( "\".3a+%2B+4.4+=+.4%28a+%2B+8%29\"
\n" ); document.write( "\".3a+%2B+4.4+=+.4a+%2B+3.2\"
\n" ); document.write( "\".1a+=+1.2\"
\n" ); document.write( "\"a+=+12\"liters
\n" ); document.write( "12 liters of the 30% solution must be added
\n" ); document.write( "check:
\n" ); document.write( "\"%28.3%2A12+%2B+.55%2A8%29+%2F+20+=+.4\"
\n" ); document.write( "\"3.6+%2B+4.4+=+20%2A.4\"
\n" ); document.write( "\"8+=+8\"
\n" ); document.write( "OK
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