document.write( "Question 127314: If I was to increase and concave the upward behavior of g(x) then this would be my results:
\n" ); document.write( "g”(x) <0 & g’(x)>0 Could you tell me if I got the answer correct? Thank you!
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Algebra.Com's Answer #93299 by stanbon(75887)\"\" \"About 
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If I was to increase and concave the upward behavior of g(x) then this would be my results:
\n" ); document.write( "g”(x) <0 & g’(x)>0 Could you tell me if I got the answer correct? Thank you!
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\n" ); document.write( "If I understand you correctly, g(x) looks like an exponential function.
\n" ); document.write( "The slope is always positive so g'(x)>0.
\n" ); document.write( "So g'(x) is always above the x axis and its values are increasing as x increases. I think g'(x) is also an exponential function.
\n" ); document.write( "If so g''(x) >0
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\n" ); document.write( "Example:
\n" ); document.write( "Say g(x)=2^x = e^(xlnx)
\n" ); document.write( "Then g'(x) = (lnx)2^x which is also an exponential function.
\n" ); document.write( "Therefore g''(x) = lnx(lnx*2^x)+(2^x(1/x)) = 2^x[(lnx)^2+(1/x)]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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