document.write( "Question 127260: I'm not sure if this is a mixture equation, but: The sum of the digits of a two digit number is 11. The number obtained by reversing the order of the digits is 27 less than the original number. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #93281 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of the digits of a two digit number is 11. The number obtained by reversing the order of the digits is 27 less than the original number. Find the original number.
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\n" ); document.write( "Let x = the original number 10's digit
\n" ); document.write( "Let y = the original number units digit
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"The sum of the digits of a two digit number is 11.\"
\n" ); document.write( " x + y = 11
\n" ); document.write( "or
\n" ); document.write( "y = (11 - x); will use this for substitution
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\n" ); document.write( "\"number obtained by reversing the order of the digits is 27 less than the original number.\"
\n" ); document.write( "10y + x = 10x + y - 27
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\n" ); document.write( "10y - y = 10x - x - 27; some basic algebra operations
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\n" ); document.write( "9y = 9x - 27
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\n" ); document.write( "y = x - 3; simplified, divided equation by 9
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\n" ); document.write( " Find the original number.
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\n" ); document.write( "Substitute (11-x) for y in the above equation
\n" ); document.write( "11 - x = x - 3
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\n" ); document.write( "11 + 3 = x + x
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\n" ); document.write( "14 = 2x
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\n" ); document.write( "x = 7 is the 10's digit
\n" ); document.write( "then
\n" ); document.write( "11 - 7 = 4 is the units digit
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\n" ); document.write( "74 is the original number
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\n" ); document.write( "Check solution using the statement:
\n" ); document.write( "\"number obtained by reversing the order of the digits is 27 less than the original number.\"
\n" ); document.write( "47 = 74 - 27; confirms our solution
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\n" ); document.write( "Could you follow what we did here? This is a good method to use on all these type of problems. \n" ); document.write( "
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